16.1x^2+60x=40

Solution for 16.1x^2+60x=40 equation:

16.1x^2+60x=40

We move all terms to the left:

16.1x^2+60x-(40)=0

a = 16.1; b = 60; c = -40;
Δ = b2-4ac
Δ = 602-4·16.1·(-40)
Δ = 6176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6176}=\sqrt{16*386}=\sqrt{16}*\sqrt{386}=4\sqrt{386}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{386}}{2*16.1}=\frac{-60-4\sqrt{386}}{32.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{386}}{2*16.1}=\frac{-60+4\sqrt{386}}{32.2}
$